Java 调用Javascript函数
2018-03-18 14:01 更新
Java脚本教程 - Java调用Javascript函数
以下代码显示了如何从Java调用Javascript函数。
首先,它定义了Javascript文件中的四个函数并保存它到c:/Java_Dev/calculator.js。
var calculator = new Object(); calculator.add = function (n1, n2) n1 + n2; calculator.subtract = function (n1, n2) n1 - n2; calculator.multiply = function (n1, n2) n1 * n2; calculator.divide = function (n1, n2) n1 / n2;
然后,使用eval()函数加载脚本并获取表示函数的Object。
String scriptPath = "c:/Java_Dev/calculator.js"; engine.eval("load("" + scriptPath + "")"); Object calculator = engine.get("calculator");
最后,通过名称获取函数并传递参数。
Object addResult = inv.invokeMethod(calculator, "add", x, y); Object subResult = inv.invokeMethod(calculator, "subtract", x, y); Object mulResult = inv.invokeMethod(calculator, "multiply", x, y); Object divResult = inv.invokeMethod(calculator, "divide", x, y);
例子
import javax.script.Invocable; import javax.script.ScriptEngine; import javax.script.ScriptEngineManager; public class Main { public static void main(String[] args) throws Exception { ScriptEngineManager manager = new ScriptEngineManager(); ScriptEngine engine = manager.getEngineByName("JavaScript"); if (!(engine instanceof Invocable)) { System.out.println("Invoking methods is not supported."); return; } Invocable inv = (Invocable) engine; String scriptPath = "c:/Java_Dev/calculator.js"; engine.eval("load("" + scriptPath + "")"); Object calculator = engine.get("calculator"); int x = 3; int y = 4; Object addResult = inv.invokeMethod(calculator, "add", x, y); Object subResult = inv.invokeMethod(calculator, "subtract", x, y); Object mulResult = inv.invokeMethod(calculator, "multiply", x, y); Object divResult = inv.invokeMethod(calculator, "divide", x, y); System.out.println(addResult); System.out.println(subResult); System.out.println(mulResult); System.out.println(divResult); } }
上面的代码生成以下结果。
这里是c:/Java_Dev/calculator.js的源代码。
var calculator = new Object(); calculator.add = function (n1, n2) n1 + n2; calculator.subtract = function (n1, n2) n1 - n2; calculator.multiply = function (n1, n2) n1 * n2; calculator.divide = function (n1, n2) n1 / n2;
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